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Show that 12 n cannot end with zero or 5

WebJan 18, 2024 · Prove that 12^n cannot end with digit 0 or 5 for any natural number nClass 10 Mathematics Chapter 1 Real Numbers Important Question. WebSolution. If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so 2 & 3 is only prime in the factorization of 6 n. Since 5 is not present in the prime factorization, there is no natural ...

12n cannot end with the digit 0 to 5 for value of n - BYJU

WebFor a number to end with 0, the number must have 2 & 5 as factors. 10=2×5 100=2 2×5 2 For a number to end with 5, the number must have 5 as a factor. 30=5×6 3 n×(2 2) m=3 n×2 2m This number dosent have 5 or 5 and 2 as its factors. Therefore the number cant end with 0 o 5. Was this answer helpful? 0 0 Similar questions WebNov 2, 2024 · To show that 12^n cannot end with 0 or 5 for any natural number n. Explanation: 12 ^n in prime factor form cn be written as, As, there is no term in the factor … how big is my onenote notebook https://gumurdul.com

Show that 12n cannot end with the digit 0 or 5 for any natural number n.

WebMar 29, 2024 · Let us take the example of a number which ends with the digit 0 So, 10 = 2 × 5 100 = 2 × 2 × 5 × 5 Here we note that numbers ending with 0 has both 2 and 5 as their prime factors Whereas 4n = (2 × 2) n Does not have 5 as a prime factor. So, it does not end with zero. Therefore, 4n cannot end with zero for any natural number n WebShow that 12 n cannot end with the digit 0 or 5 for any natural number n. Answers (1) We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5. Here 12n … WebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This … how many ounces are in 1/4 cup

Number of zeros not possible in $n!$ - Mathematics Stack Exchange

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Show that 12 n cannot end with zero or 5

Show that $12^n$ cannot end with the digit 0 or 5 for any …

WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 … WebJan 18, 2024 · See answer. 12 to the power n cannot end with the digit 0 or 5 because for a number to end with the digit 0 or 5,it should have 2 and 5 both in its prime factorization. …

Show that 12 n cannot end with zero or 5

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WebAug 26, 2024 · Best answer If any number ends with the digit 0 or 5, it is always divisible by 5. This is possible only if prime factorisation of 12n 12 n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 22 × 3 12 = 2 × 2 × 3 = 2 2 × 3 ⇒ 12m = (22 × 3)n = 22n × 3m ⇒ 12 m = ( 2 2 × 3) n = 2 2 n × 3 m [Since, there is no term contains 5] WebTo Show :- 12 n cannot end with 0 Proof :-12 n = 4 n x 3 m = 2 n x 3 m But the formula of factorisation tells that the numbers can end with 0 or 5 when they are in form of 2 n + 5 m …

WebApr 21, 2024 · For a number to be end with digit zero its prime factors must have atleast one 2 and A are 5 both and for a number to be end with 5 its prime factors must have at least … WebIf any number ends with the digit 0 that means it should be divisible by 5. That is, if 6 n ends with the digit 0, then the prime factorisation of 6 n would contain the prime number 5. Prime factors of 6 n = (2 × 3) n = (2) n × (3) n. We can clearly observe, 5 is not present in the prime factors of 6 n. That means 6 n will not be divisible by 5.

WebShow that (12) n cannot end with digit 0 or 5 for any natural number n. Answers (1) There is no factor of the form 5 n, therefore, 12 n can not end with digit 0 or 5 for any natural … WebOct 10, 2024 · If 12 n ends with the digit zero it must be divisible by 5. This is possible only if the prime factorisation of 12 n contains the prime number 5. The prime factorisation of 12 …

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WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be … how big is my microwaveWebnews presenter, entertainment 2.9K views, 17 likes, 16 loves, 62 comments, 6 shares, Facebook Watch Videos from GBN Grenada Broadcasting Network: GBN News 12th April 2024 Anchor: Stasia Blake GBN... how big is my memoryWebHere, Number=12 n where n stand for any natural number . Now 12 n = (2 2 x3) n. Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to … how many ounces are in 1.6 quartsWebJul 17, 2014 · 25 n = (5 X 5) n If we raise 5 to any power ,unit digit will only be 5 . For any natural number to end with 0 , it must be a factor of 10 so it must have factors both 2 and 5 .But 25 does not have 2 as a factor. Thus 25 n cannot end with 0 for any natural number n Hope this would have cleared your doubt . how many ounces are in 1 and a half cupshow many ounces are in 1 liter of fluidWebSolution. If any number ends with the digit 0 or 5. It is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of … how big is my one drive storageWebIf 12 n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12^n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 2 2 × 3 ⇒ 12 n = … how many ounces are in 1.7 liters