WebJan 18, 2024 · Prove that 12^n cannot end with digit 0 or 5 for any natural number nClass 10 Mathematics Chapter 1 Real Numbers Important Question. WebSolution. If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so 2 & 3 is only prime in the factorization of 6 n. Since 5 is not present in the prime factorization, there is no natural ...
12n cannot end with the digit 0 to 5 for value of n - BYJU
WebFor a number to end with 0, the number must have 2 & 5 as factors. 10=2×5 100=2 2×5 2 For a number to end with 5, the number must have 5 as a factor. 30=5×6 3 n×(2 2) m=3 n×2 2m This number dosent have 5 or 5 and 2 as its factors. Therefore the number cant end with 0 o 5. Was this answer helpful? 0 0 Similar questions WebNov 2, 2024 · To show that 12^n cannot end with 0 or 5 for any natural number n. Explanation: 12 ^n in prime factor form cn be written as, As, there is no term in the factor … how big is my onenote notebook
Show that 12n cannot end with the digit 0 or 5 for any natural number n.
WebMar 29, 2024 · Let us take the example of a number which ends with the digit 0 So, 10 = 2 × 5 100 = 2 × 2 × 5 × 5 Here we note that numbers ending with 0 has both 2 and 5 as their prime factors Whereas 4n = (2 × 2) n Does not have 5 as a prime factor. So, it does not end with zero. Therefore, 4n cannot end with zero for any natural number n WebShow that 12 n cannot end with the digit 0 or 5 for any natural number n. Answers (1) We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5. Here 12n … WebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This … how many ounces are in 1/4 cup